SELECT ID, Desc FROM tblBits WHERE ID > 0 AND ID & (ID-1) = 0

How does this work?

Every power of two when converted to binary has only one bit set.
For example: 4=100, 8=1000, 16=10000
And one digit less in binary looks like:
3 = 011, 7=0111, 15=01111

So an AND operation between {4,3}, {8,7}, {16,15} and so on will always yield a ‘0′

--Create Table
CREATE TABLE T1 (
    a INT,
    b INT,
    operator CHAR,
    c AS CASE operator
        WHEN '+' THEN a+b
        WHEN '-' THEN a-b
        ELSE a*b
    END
    PERSISTED
) ;

--Insert dummy data into it
INSERT INTO T1 VALUES(1,2,'+')
INSERT INTO T1 VALUES(5,3,'-')
INSERT INTO T1 VALUES(4,4,'')

--View the results
SELECT * FROM T1

Notice the keyword PERSISTED. This will enable the computed column value to be stored physically on to the disk so that it need not be created every time you ask for it. Creating an index on this computed column will improve performance by doing a seek rather than a table scan.

If you want to specify the above computed column in SQL Server management studio directly you can do this:

Modify the table. Go to the computed column specification for the specific column. Expand it and type the following in the “Formula” field:

(CASE [operator] WHEN '+' THEN [a]+[b] WHEN '-' THEN [a]-[b]

ELSE [a]*[b] END)

Enter without line breaks. If you want the column values to be persisted in the storage medium, just change the value of “Is Persisted” to “Yes”

Table
=====
1    One
2    Two
3    Three
4    Four

to the following:

Output
======
One, Two, Three, Four

Here is a simple way to do it:

SQL Server 2005:

SELECT STUFF(SELECT ‘, ‘ + ColumnName FROM TableName FOR XML PATH(”),1,2,”)

SQL Server 2000:

DECLARE @t varchar(4000)
SET @t = ”
SELECT @t = @t + ‘, ‘ + ColumnName From TableName
SELECT STUFF(@t,1,2,”)

STUFF() deletes a specified length of characters and inserts another set of characters at a specified starting point.

sys.fn_sqlvarbasetostr

The above function will in turn call

sys.fn_varbintohexsubstring

in our case because we are trying to convert binary to string. To use the function in a select query just do so:

SELECT sys.fn_sqlvarbasetostr(MD5Hash) From HashTable

where MD5Hash is the binary column you would like to convert.

DECLARE @idoc int
DECLARE @idoc1 int
DECLARE @doc varchar(1000)
DECLARE @doc1 varchar(1000)
SET @doc =’<ROOT><Customer CustomerID=”1″ ContactName=”Balaji Ramesh” /></ROOT>’
SET @doc1 =’<ROOT><Customer CustomerID=”1″ ContactNumber=”1234567890″ /></ROOT>’
–Create an internal representation of the XML document.
EXEC sp_xml_preparedocument @idoc OUTPUT, @doc
EXEC sp_xml_preparedocument @idoc1 OUTPUT, @doc1
– Execute a SELECT statement that uses the OPENXML rowset provider.

SELECT d1.*, d2.ContactNumber
FROM  OPENXML (@idoc, ‘/ROOT/Customer’,1)
            WITH (CustomerID  varchar(10),
                  ContactName varchar(20)) as d1
INNER JOIN
OPENXML (@idoc1, ‘/ROOT/Customer’,1)
            WITH (CustomerID  varchar(10),
                  ContactNumber varchar(20)) as d2
ON d1.CustomerID = d2.CustomerID

EXEC sp_xml_removedocument @idoc
EXEC sp_xml_removedocument @idoc1

This is a simple example but you get the idea.

SET Identity_Insert <TableName> ON

Now you will be able to insert a value into the identity column. Once done just revert the above statement to what follows to avoid unnecessary inserts:

SET Identity_Insert <TableName> OFF